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Hur konverterar jag snabbt datum till ord i Excel?

I allmänhet konverterar vi vanligtvis datumet till andra datumformat eller siffror i Excel, men har du någonsin stött på ett problem med att konvertera datumet till engelska ord som bilden nedan visas? Egentligen finns det ingen inbyggd funktion som kan hantera den utan en VBA-kod.
doc datum till ord 1

Konvertera datum till ord med definierad funktion


Konvertera datum till ord med definierad funktion

Här är en makrokod som kan göra dig en tjänst när du konverterar datum till ord.

1. Aktivera det ark du använder och tryck på Alt + F11 nycklar för att öppna Microsoft Visual Basic för applikationer fönster.

2. klick Insert > Modulerna och klistra in under koden i skriptet.

VBA: Konvertera datum till ord

Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Hundreds As String
    Dim Decades As String
    Dim xTensArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If
        Hundreds = Mid$(xYear, 2, 1)
    If CInt(Hundreds) Then
        Hundreds = xCardArr(CInt(Hundreds)) & " Hundred "
    Else
        Hundreds = ""
    End If
    DateToWords = xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  xCardArr(CInt(Left$(xYear, 1))) & _
                  " Thousand " & Hundreds & Decades
End Function

doc datum till ord 2

3. Spara koden och gå tillbaka till arket, välj en cell som du ska skriva ut resultatet i, skriv den här formeln = DateToWords (A1) (A1 är det datum du använder), tryck på ange tangent och dra handtaget för automatisk fyllning till över cellerna du behöver. Se skärmdump:
doc datum till ord 3


Siffror till ord

doc stava ut nummer 1

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Comments (23)
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This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST TWENTY HUNDRED NINETY-EIGHT
In this vba have error
convert it1998 but it shows TWENTY HUNDRED NINETY-EIGHT
This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST NINETEEN HUNDRED NINETY EIGHT
I need dob into words in upper format but i use this micros in excel i got this
07/08/1998 SEVENTH AUGUST ONE THOUSAND NINE HUNDRED NINETY-EIGHT which is not usefull
This comment was minimized by the moderator on the site
Hi, MAX, I have modified the VBA, please try and let me know if it works. Thanks.
Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Decades As String
    Dim years As String
    Dim xTensArr As Variant
    Dim xyearArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    
    
      xyearArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")

    years = xyearArr(CInt(Year(xRgVal) / 100)) & " Hundred"
    
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If

    DateToWords = UCase(xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  years & " " & Decades)
End Function

This comment was minimized by the moderator on the site
07/08/1998 SEVENTH AUGUST TWENTY HUNDRED NINETY-EIGHT
In this vba have error
convert it1998 but it shows TWENTY HUNDRED NINETY-EIGHT
This comment was minimized by the moderator on the site
Hi, try this vba:
Function DateToWords(ByVal xRgVal As Date) As String
'UpdatebyExtendoffice20170926
    Dim xYear As String
    Dim Decades As String
    Dim years As String
    Dim xTensArr As Variant
    Dim xyearArr As Variant
    Dim xOrdArr As Variant
    Dim xCardArr As Variant
    xOrdArr = Array("First", "Second", "Third", _
                   "Fourth", "Fifth", "Sixth", _
                   "Seventh", "Eighth", "Nineth", _
                   "Tenth", "Eleventh", "Twelfth", _
                   "Thirteenth", "Fourteenth", _
                   "Fifteenth", "Sixteenth", _
                   "Seventeenth", "Eighteenth", _
                   "Nineteenth", "Twentieth", _
                   "Twenty-first", "Twenty-second", _
                   "Twenty-third", "Twenty-fourth", _
                   "Twenty-fifth", "Twenty-sixth", _
                   "Twenty-seventh", "Twenty-eighth", _
                   "Twenty-nineth", "Thirtieth", _
                   "Thirty-first")
    xCardArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen")
    xTensArr = Array("Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")
    xYear = CStr(Year(xRgVal))
    
    
      xyearArr = Array("", "One", "Two", "Three", "Four", _
                   "Five", "Six", "Seven", "Eight", "Nine", _
                   "Ten", "Eleven", "Twelve", "Thirteen", _
                   "Fourteen", "Fifteen", "Sixteen", _
                   "Seventeen", "Eighteen", "Nineteen", "Twenty", "Thirty", "Forty", "Fifty", _
               "Sixty", "Seventy", "Eighty", "Ninety")

    years = xyearArr(Fix(Year(xRgVal) / 100)) & " Hundred"
    
    Decades = Mid$(xYear, 3)
    If CInt(Decades) < 20 Then
        Decades = xCardArr(CInt(Decades))
    Else
        Decades = xTensArr(CInt(Left$(Decades, 1)) - 2) & "-" & _
                xCardArr(CInt(Right$(Decades, 1)))
    End If

    DateToWords = UCase(xOrdArr(Day(xRgVal) - 1) & _
                  Format$(xRgVal, " mmmm ") & _
                  years & " " & Decades)
End Function

This comment was minimized by the moderator on the site
آپ کا بہت شکریہ
This comment was minimized by the moderator on the site
It is giving the #NAME? Error
This comment was minimized by the moderator on the site
I would like to add text to the output, for instance, 1958 gets converted to One Thousand Nineteen Hundred Fifty Eight and I would like it to say One Thousand Nineteen Hundred and Fifty Eight. Can someone give me an example of how I can do this please?
This comment was minimized by the moderator on the site
thank u for helping me . very useful in converting date of birth in word
This comment was minimized by the moderator on the site
Sir/Madam

It is very useful for me.

Really Amazing and helped to solve the problem within a minute.

Thank you for uploading this document. Very nice
This comment was minimized by the moderator on the site
how to use this code in vb6 for a textbox
This comment was minimized by the moderator on the site
date to word in gujarati language avilable ? please answer me. 9427909038
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I think it does not work for other languages except english.
This comment was minimized by the moderator on the site
Hello can we also do this in word docx?
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